u^2-4u-20=3u+2=

Solution for u^2-4u-20=3u+2= equation:

u^2-4u-20=3u+2=

We move all terms to the left:

u^2-4u-20-(3u+2)=0

We get rid of parentheses

u^2-4u-3u-2-20=0

We add all the numbers together, and all the variables

u^2-7u-22=0

a = 1; b = -7; c = -22;
Δ = b2-4ac
Δ = -72-4·1·(-22)
Δ = 137
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{137}}{2*1}=\frac{7-\sqrt{137}}{2}
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{137}}{2*1}=\frac{7+\sqrt{137}}{2}
$